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b = [ [ i, d for d in range ( 4 ) ] for i in range ( 4 ) ]
Хочу получить [[0,0],[0,1],[0,2],[0,3],[1,0],[1,1] ...
Size: a a a
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А4
DB
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for x in ...: for y in ...:
но такое себе, мне кажется было бы более натурально если бы comprehension работал бы наоборотxs = []
for x in ...:
for y in ...:
xs.append((x, y))
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DB
itertools.product([0, 1, 2, 3, 4], repeat=2)
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EXPLAIN ANALYZE ...
Planning Time: 0.487 ms
JIT:
Functions: 101
Options: Inlining true, Optimization true, Expressions true, Deforming true
Timing: Generation 9.688 ms, Inlining 13.668 ms, Optimization 190.746 ms, Emission 173.430 ms, Total 387.532 ms
Execution Time: 390.983 ms
SET jit = off
EXPLAIN ANALYZE ...
Planning Time: 0.623 ms
Execution Time: 2.110 ms
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DA
EXPLAIN ANALYZE ...
Planning Time: 0.487 ms
JIT:
Functions: 101
Options: Inlining true, Optimization true, Expressions true, Deforming true
Timing: Generation 9.688 ms, Inlining 13.668 ms, Optimization 190.746 ms, Emission 173.430 ms, Total 387.532 ms
Execution Time: 390.983 ms
SET jit = off
EXPLAIN ANALYZE ...
Planning Time: 0.623 ms
Execution Time: 2.110 ms
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