H
Sudha
Actually variable are not getting value assigned
Size: a a a
2020 September 08
S
I am assigning it to an argument...
H
How do you mapping import arguments
H
Can u recheck those
B
Sudha
How are you splitting it.. after split it is in an array or list ..
S
As you can see...I did a Name.Split(" "c)(0)
S
Split returns a string or an array
H
It's a string
B
Sudha
Split returns a string or an array
Exactly ...
S
Okk...then where is the issue...can't figure out
B
Write FirstName(0).tostring ..
S
Write FirstName(0).tostring ..
Tried that too...it doesnt matter...plus the seq works fine when running it individually
B
And FirstName should be.. dfined as String[] .. string array ..
B
In argument type ..
S
And FirstName should be.. dfined as String[] .. string array ..
But when running the seq individually...assigning the .split o/p to a string works fine
H
Sudha
Can you try giving . Tostring to your expression
S
S
.Split returns a string as mentioned in the error description
H
I think u are correct before as u where passing 0 as index to return a object of a array.
H
Sudha
.Split returns a string as mentioned in the error description
If your using string array variable remove the index value i.e. (0) from your expression