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DN
NB
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SELECT * FROM contacts_lists JOIN users ON contact_id = id WHERE user_id = 1;
работает хорошо, ноSELECT (user_id, contact_id, group_id, login) FROM contacts_lists JOIN users ON contact_id = id WHERE user_id = 1;
выдает Error: row value misused
SQLite. что делать?AM
AM
G
SELECT (t1.user_id, t1.contact_id, t1.group_id, t2.login) FROM contacts_lists t1 JOIN users t2 ON t1.contact_id = t2.id WHERE t1.user_id = 1;
SD
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SELECT contact_id, group_id, login, first_name, second_name, status
FROM contacts_lists AS cl
JOIN users AS u ON cl.contact_id = u.id
JOIN users_profiles AS up ON cl.contact_id = up.user_id
WHERE cl.user_id = 1;
SELECT contact_id, group_id, login, first_name, second_name, status
FROM contacts_lists AS cl, users AS u, users_profiles AS up
WHERE cl.contact_id = u.id AND cl.contact_id = up.user_id AND cl.user_id = 1;
NB
SELECT contact_id, group_id, login, first_name, second_name, status
FROM contacts_lists AS cl
JOIN users AS u ON cl.contact_id = u.id
JOIN users_profiles AS up ON cl.contact_id = up.user_id
WHERE cl.user_id = 1;
SELECT contact_id, group_id, login, first_name, second_name, status
FROM contacts_lists AS cl, users AS u, users_profiles AS up
WHERE cl.contact_id = u.id AND cl.contact_id = up.user_id AND cl.user_id = 1;
G
SELECT contact_id, group_id, login, first_name, second_name, status
FROM contacts_lists AS cl
JOIN users AS u ON cl.contact_id = u.id
JOIN users_profiles AS up ON cl.contact_id = up.user_id
WHERE cl.user_id = 1;
SELECT contact_id, group_id, login, first_name, second_name, status
FROM contacts_lists AS cl, users AS u, users_profiles AS up
WHERE cl.contact_id = u.id AND cl.contact_id = up.user_id AND cl.user_id = 1;
AM